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  1. A wooden fossil has a c-14 activity of 6.3 beta particles ... - Socratic

    Feb 20, 2018 · A wooden fossil has a c-14 activity of 6.3 beta particles/min/gram of carbon.calculate the age of the fossil if half life of carbon is 5760 yrs?

  2. Question #859bc - Socratic

    Jun 20, 2017 · Using the half-angle formula for cosine: cos (theta/2) = +-sqrt ( (1+costheta)/2) Therefore...with theta = arcsin (3/5) cos ( (1/2)arcsin (3/5)) = +-sqrt ( ( (1+cos (arcsin (3/5)))/2) Now, …

  3. Question #65c13 - Socratic

    Think about the conversion of C-14 to N-14 which is a beta decay process which has a half life of about 5,700 years. If you start with 100 C-14 atoms, after 5,700 years (one half life) you should only have …

  4. Question #4cd61 - Socratic

    Since it is not logical to have half an atom multiple the ratio by 2 2.5/1 xx 2/2 = 5/2 There are five Hydrogen to 2 Carbons This is the empirical formula. ( It may not be the molecular formula)

  5. Question #265f1 - Socratic

    Explanation: Starting with #sin (x/2)-cosx=0#, use the half angle formula for #sin (x/2)#: #sin (x/2)=sqrt ( (1-cosx)/2)# and rewrite the original equation: #sqrt ( (1-cosx)/2)-cosx=0# Add #cosx# to both sides: …

  6. Exponential Growth and Decay Models - Socratic

    How do you Find exponential decay half life? How do you graph exponential decay? How do you find the equation of exponential decay? How do you use the exponential decay formula? What does …

  7. Topic:half-life decay 2.80moles of a radioactive element was ... - Socratic

    Topic:half-life decay 2.80moles of a radioactive element was originally present in a given sample of compound.if after 45.6moles of it remain,find the half life of this element?

  8. The perimeter of a triangle is 79.75 inches. The second side of the ...

    The Longest side is ofcourse c.. as b=a/2 and a=a and c=a+7.25 For a starter... just imagine a triangle in your head Now let that second side you were talking about be b.. it is half as big as the a side.. which …

  9. The level of thorium in a sample decreases by a factor of one-half ...

    Explanation: Let us write the expression as follows: # (1/2)^N=7.6%# N being the number of half times passed, Since after each half life, the value is halved. Now that we have the unknown, number of half …

  10. How do you use Heron's formula to find the area of a ... - Socratic

    In order to use Heron's formula, we will have to know the semiperimeter of the triangle. The semiperimeter is simply one half the perimeter of the triangle, so the semiperimeter #s# of a triangle …